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| Name | A vessel is in the form of inverted cone its height is 8 cm and the radius of its top which is open |
| Video Uploader | Video From Focus Classes - Maths 9 & 10 |
| Upload Date | This Video Uploaded At 05-11-2019 12:34:46 |
| Video Discription | Class-10, Maths Chapter- 13, Surface Areas and Volumes A vessel is in the form of inverted cone its height is 8 cm and the radius of its top which is open is 5 centimetre it is filled with water up to the brim when lead shots each of which is a sphere of radius 0.5 cm are dropped into the vessels one fourth of water flow out find the number of lead shot drop into the vessels. Class 10, Most Important Question for Board Exam. Most Important Question for Board Exam from Probability. Rd Sharma question from Probability 👉👉If you want, You can consider donation through PhonePe No.- 8273007746 to bring even better videos for you people. 🔶We have covered all the questions from NCERT Book, RD Sharma, RS Agarwal, Previous Year's Papers, Most Repeated Questions in Board Exam, Questios from various Sample Papers, Important Questions from different Board Exams also from AMU - Entrance Papers. 🔶Visit our Playlists- ◼️◾Extra Questions (Most Important Questions for Board Exam)◾◼️ 👉https://bit.ly/2JtCBnL Chapter 1: Real Numbers 👉https://bit.ly/3dIG9k2 Chapter 2: Polynomials 👉https://bit.ly/33ZTM9X Chapter 3: Pair of linear Equations in Two Variables 👉https://bit.ly/2UxsZ1R Chapter 4: Quadratic Equations 👉https://bit.ly/3bxIgoW Chapter 5: Arithmetic Progression 👉https://bit.ly/2wR6oEi Chapter 6: Triangles 👉https://bit.ly/2QXb828 Chapter 7: Coordinate Geometry 👉https://bit.ly/2UTybfl Chapter 8: Introduction to Trigonometry 👉https://bit.ly/3ayeZKz Chapter 9: Some Applications of Trigonometry 👉https://bit.ly/2V3RrXJ Chapter 10: Circles 👉https://bit.ly/2xyBLn3 Chapter 11: Constructions 👉https://bit.ly/39wPDLV Chapter 12: Area Related to Circles 👉https://bit.ly/3aywDOs Chapter 13: Surface Areas and Volumes 👉https://bit.ly/3dLOtiK Chapter 14: Statistics 👉https://bit.ly/2w2OZrT Chapter-15: Probability 👉https://rb.gy/9q9dhy. ◾Deepak Rajoria (Maths Teacher) ◾Focus Classes #FocusClasses, #DeepakRajoria, #SurfaceAreasAndVolumes Surface Area of a Cuboid = 2(lb + bh + hl) Surface Area of a cube = 6a2 Surface Area of a cone = πrl Surface Area of a cylinder = 2πrh Total surface area of a cylinder = 2πr(r + h) Total surface area of a cone = πr(r + l) Surface Area of a hemisphere = 2πr2 Surface Area of a hemisphere = 3πr2 Surface Area of a frustum = π(r1+ r2)l Total Surface Area of a frustum = π(r1+ r2)l + πr1^2+ πr2^2 Slant Height of a cone l = √(r2 + h2) Relation between slant height, radius and height of a cone. Surface Area and volume of a hollow cylinder Surface Area and volume of a shell Volume of a frustum of a cone = 1/3 π(r1^2 + r2^2 +r1.r2)h Curved surface area of a frustum of a cone = πl(r1 + r2) Total surface area of frustum of a cone = πl(r1 + r2) + π(r1^2+ r2^2) . |
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| Tags | Derivation of Volume | Focus Classes | Maths with Deepak Rajoria | Surface Areas and Volumes | Class 10 maths | mensuration problems | Most important question for board exam | CBSE Maths | NCERT books questio | Class 10 Maths Ex 13.2 Q5 | Ncert Maths class 10 Ex 13.2 Q5 | Class 10th Maths Ch 13 Surface Areas and Volumes | A vessel is in the form of inverted cone its height is 8 cm | Most important question from Surface areas and Volumes class 10 |
