X Y Z = 3

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A Diophantine System (x^3+y^3+z^3=x+y+z=3)
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x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)/a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)
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Prove that (x+y)^3+(y+z)^3+(z+x)^3-3(x+y)(y+z)(z+x)=2(x^3+y^3+z^3-3xyz).
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Class 10 TN 3.Algebra Example 3.3 TN 3x-2y+z = 2, 2x+3y-z=5, x+y+z=5 .
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if x:y:z = 3:4:5 and x+y+z = 96, then what is the value of z ?
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MathWithNazia : Algebraic identities example, If x+y+z=8 ; xy+yz+zx= 20 find x^3+y^3+z^3- 3xyz
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if x + Y + Z is equal to 10 ,X² + Y² + Z² is equal to 30 then find the value of x ³ +y³+z³ - 3 x y z
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